(2b-3)/7-(b)/2=(b+3)/14

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Solution for (2b-3)/7-(b)/2=(b+3)/14 equation:


(2b-3)/7-(b)/2=(b+3)/14

We simplify the equation to the form, which is simple to understand 
(2b-3)/7-(b)/2=(b+3)/14

Reorder the terms in parentheses
( + 0.285714285714b-0.428571428571)-(b)/2=(b+3)/14

Remove unnecessary parentheses
 + 0.285714285714b-0.428571428571-(b)/2=(b+3)/14

Reorder the terms in parentheses
 + 0.285714285714b-0.428571428571-( + 0.5b)=(b+3)/14

Remove unnecessary parentheses
 + 0.285714285714b-0.428571428571-0.5b=(b+3)/14

Reorder the terms in parentheses
 + 0.285714285714b-0.428571428571-0.5b=( + 0.0714285714286b + 0.214285714286)

Remove unnecessary parentheses
 + 0.285714285714b-0.428571428571-0.5b=0.0714285714286b + 0.214285714286

We move all terms containing b to the left and all other terms to the right. 
 + 0.285714285714b-0.5b-0.0714285714286b=0.214285714286 + 0.428571428571

We simplify left and right side of the equation. 
-0.285714285714b=0.642857142857

We divide both sides of the equation by -0.285714285714 to get b. 
b=-2.25

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