(2b-4)(b+2)=

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Solution for (2b-4)(b+2)= equation:


Simplifying
(2b + -4)(b + 2) = 0

Reorder the terms:
(-4 + 2b)(b + 2) = 0

Reorder the terms:
(-4 + 2b)(2 + b) = 0

Multiply (-4 + 2b) * (2 + b)
(-4(2 + b) + 2b * (2 + b)) = 0
((2 * -4 + b * -4) + 2b * (2 + b)) = 0
((-8 + -4b) + 2b * (2 + b)) = 0
(-8 + -4b + (2 * 2b + b * 2b)) = 0
(-8 + -4b + (4b + 2b2)) = 0

Combine like terms: -4b + 4b = 0
(-8 + 0 + 2b2) = 0
(-8 + 2b2) = 0

Solving
-8 + 2b2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 2b2 = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 2b2 = 0 + 8
2b2 = 0 + 8

Combine like terms: 0 + 8 = 8
2b2 = 8

Divide each side by '2'.
b2 = 4

Simplifying
b2 = 4

Take the square root of each side:
b = {-2, 2}

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