(2b-4)/4=(4b+3)/3

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Solution for (2b-4)/4=(4b+3)/3 equation:



(2b-4)/4=(4b+3)/3
We move all terms to the left:
(2b-4)/4-((4b+3)/3)=0
We calculate fractions
2b/()+(-((4b+3)*4)/()=0
We calculate terms in parentheses: +(-((4b+3)*4)/(), so:
-((4b+3)*4)/(
We multiply all the terms by the denominator
-((4b+3)*4)
We calculate terms in parentheses: -((4b+3)*4), so:
(4b+3)*4
We multiply parentheses
16b+12
Back to the equation:
-(16b+12)
We get rid of parentheses
-16b-12
Back to the equation:
+(-16b-12)
We get rid of parentheses
2b/()-16b-12=0
We multiply all the terms by the denominator
2b-16b*()-12*()=0
We add all the numbers together, and all the variables
2b-16b*()=0

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