(2b-4)2=(b-1)

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Solution for (2b-4)2=(b-1) equation: 



(2b-4)2=(b-1)

We move all terms to the left:

(2b-4)2-((b-1))=0

We multiply parentheses

4b-((b-1))-8=0



We calculate terms in parentheses: -((b-1)), so:

(b-1)

We get rid of parentheses

b-1

Back to the equation:

-(b-1)



We get rid of parentheses

4b-b+1-8=0

We add all the numbers together, and all the variables

3b-7=0

We move all terms containing b to the left, all other terms to the right

3b=7

b=7/3

b=2+1/3

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