(2b-45)+(3b-20)+(2b-28)=180

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Solution for (2b-45)+(3b-20)+(2b-28)=180 equation: 



(2b-45)+(3b-20)+(2b-28)=180

We move all terms to the left:

(2b-45)+(3b-20)+(2b-28)-(180)=0

We get rid of parentheses

2b+3b+2b-45-20-28-180=0

We add all the numbers together, and all the variables

7b-273=0

We move all terms containing b to the left, all other terms to the right

7b=273

b=273/7

b=39

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