(2b-5)+(b*2)+(c+3)=20

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Solution for (2b-5)+(b*2)+(c+3)=20 equation:


Simplifying
(2b + -5) + (b * 2) + (c + 3) = 20

Reorder the terms:
(-5 + 2b) + (b * 2) + (c + 3) = 20

Remove parenthesis around (-5 + 2b)
-5 + 2b + (b * 2) + (c + 3) = 20

Reorder the terms for easier multiplication:
-5 + 2b + (2b) + (c + 3) = 20

Reorder the terms:
-5 + 2b + (2b) + (3 + c) = 20

Remove parenthesis around (3 + c)
-5 + 2b + (2b) + 3 + c = 20

Reorder the terms:
-5 + 3 + 2b + (2b) + c = 20

Combine like terms: -5 + 3 = -2
-2 + 2b + (2b) + c = 20

Combine like terms: 2b + (2b) = 4b
-2 + 4b + c = 20

Solving
-2 + 4b + c = 20

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 4b + 2 + c = 20 + 2

Reorder the terms:
-2 + 2 + 4b + c = 20 + 2

Combine like terms: -2 + 2 = 0
0 + 4b + c = 20 + 2
4b + c = 20 + 2

Combine like terms: 20 + 2 = 22
4b + c = 22

Add '-1c' to each side of the equation.
4b + c + -1c = 22 + -1c

Combine like terms: c + -1c = 0
4b + 0 = 22 + -1c
4b = 22 + -1c

Divide each side by '4'.
b = 5.5 + -0.25c

Simplifying
b = 5.5 + -0.25c

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