(2b-5)+b+(b+80)=982

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Solution for (2b-5)+b+(b+80)=982 equation: 



(2b-5)+b+(b+80)=982

We move all terms to the left:

(2b-5)+b+(b+80)-(982)=0

We add all the numbers together, and all the variables

b+(2b-5)+(b+80)-982=0

We get rid of parentheses

b+2b+b-5+80-982=0

We add all the numbers together, and all the variables

4b-907=0

We move all terms containing b to the left, all other terms to the right

4b=907

b=907/4

b=226+3/4

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