(2b-5)/7=b/3

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Solution for (2b-5)/7=b/3 equation: 


b in (-oo:+oo)

(2*b-5)/7 = b/3 // - b/3

(2*b-5)/7-(b/3) = 0

(2*b-5)/7-b/3 = 0

(3*(2*b-5))/(3*7)+(7*(-b))/(3*7) = 0

3*(2*b-5)+7*(-b) = 0

-b-15 = 0

(-b-15)/(3*7) = 0

(-b-15)/(3*7) = 0 // * 3*7

-b-15 = 0

-b-15 = 0 // + 15

-b = 15 // * -1

b = -15

b = -15

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