(2b-6)+(6b-78)=180

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Solution for (2b-6)+(6b-78)=180 equation: 



(2b-6)+(6b-78)=180

We move all terms to the left:

(2b-6)+(6b-78)-(180)=0

We get rid of parentheses

2b+6b-6-78-180=0

We add all the numbers together, and all the variables

8b-264=0

We move all terms containing b to the left, all other terms to the right

8b=264

b=264/8

b=33

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