(2b-a)/c=(-1d)/2

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Solution for (2b-a)/c=(-1d)/2 equation: 


x in (-oo:+oo)

(2*b-a)/c = (-1*d)/2 // - (-1*d)/2

(2*b-a)/c-((-1*d)/2) = 0

(2*b-a)/c+(1/2)*d = 0

(2*b-a)/c+d/2 = 0

(2*(2*b-a))/(2*c)+(c*d)/(2*c) = 0

2*(2*b-a)+c*d = 0

4*b-2*a+c*d = 0

(4*b-2*a+c*d)/(2*c) = 0

(4*b-2*a+c*d)/(2*c) = 0 // * 2*c

4*b-2*a+c*d = 0

x belongs to the empty set

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