(2b-a)/c=1/2(d)

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Solution for (2b-a)/c=1/2(d) equation: 


x in (-oo:+oo)

(2*b-a)/c = (1/2)*d // - (1/2)*d

(2*b-a)/c-((1/2)*d) = 0

(2*b-a)/c+(-1/2)*d = 0

(2*b-a)/c-d/2 = 0

(2*(2*b-a))/(2*c)+(c*(-d))/(2*c) = 0

2*(2*b-a)+c*(-d) = 0

4*b-2*a-(c*d) = 0

(4*b-2*a-(c*d))/(2*c) = 0

(4*b-2*a-(c*d))/(2*c) = 0 // * 2*c

4*b-2*a-(c*d) = 0

x belongs to the empty set

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