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(2b/3)-(1/6)=(b/2)
We move all terms to the left:
(2b/3)-(1/6)-((b/2))=0
We add all the numbers together, and all the variables
(+2b/3)-((+b/2))-(+1/6)=0
We get rid of parentheses
2b/3-((+b/2))-1/6=0
We calculate fractions
24b^2/()+(-((+b*3*6)/()+()/()=0
We calculate terms in parentheses: +(-((+b*3*6)/()+()/(), so:
-((+b*3*6)/()+()/(
We can not solve this equation
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