(2b/7)-(3-3b)/2+1=0

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Solution for (2b/7)-(3-3b)/2+1=0 equation: 


b in (-oo:+oo)

(2*b)/7-((3-(3*b))/2)+1 = 0

(2*b)/7-((3-3*b)/2)+1 = 0

(-1*(3-3*b))/2+(2*b)/7+1 = 0

(-1*7*(3-3*b))/(2*7)+(2*2*b)/(2*7)+(1*2*7)/(2*7) = 0

2*2*b-1*7*(3-3*b)+1*2*7 = 0

25*b-21+14 = 0

25*b-7 = 0

(25*b-7)/(2*7) = 0

(25*b-7)/(2*7) = 0 // * 2*7

25*b-7 = 0

25*b-7 = 0 // + 7

25*b = 7 // : 25

b = 7/25

b = 7/25

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