(2c)i+1=-d+6-i

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Solution for (2c)i+1=-d+6-i equation:


Simplifying
(2c) * i + 1 = -1d + 6 + -1i

Remove parenthesis around (2c)
2c * i + 1 = -1d + 6 + -1i

Multiply c * i
2ci + 1 = -1d + 6 + -1i

Reorder the terms:
1 + 2ci = -1d + 6 + -1i

Reorder the terms:
1 + 2ci = 6 + -1d + -1i

Solving
1 + 2ci = 6 + -1d + -1i

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2ci = 6 + -1d + -1 + -1i

Combine like terms: 1 + -1 = 0
0 + 2ci = 6 + -1d + -1 + -1i
2ci = 6 + -1d + -1 + -1i

Reorder the terms:
2ci = 6 + -1 + -1d + -1i

Combine like terms: 6 + -1 = 5
2ci = 5 + -1d + -1i

Divide each side by '2i'.
c = 2.5i-1 + -0.5di-1 + -0.5

Simplifying
c = 2.5i-1 + -0.5di-1 + -0.5

Reorder the terms:
c = -0.5 + -0.5di-1 + 2.5i-1

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