(2c+1)+8(-5c+2)=

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Solution for (2c+1)+8(-5c+2)= equation:


Simplifying
(2c + 1) + 8(-5c + 2) = 0

Reorder the terms:
(1 + 2c) + 8(-5c + 2) = 0

Remove parenthesis around (1 + 2c)
1 + 2c + 8(-5c + 2) = 0

Reorder the terms:
1 + 2c + 8(2 + -5c) = 0
1 + 2c + (2 * 8 + -5c * 8) = 0
1 + 2c + (16 + -40c) = 0

Reorder the terms:
1 + 16 + 2c + -40c = 0

Combine like terms: 1 + 16 = 17
17 + 2c + -40c = 0

Combine like terms: 2c + -40c = -38c
17 + -38c = 0

Solving
17 + -38c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-17' to each side of the equation.
17 + -17 + -38c = 0 + -17

Combine like terms: 17 + -17 = 0
0 + -38c = 0 + -17
-38c = 0 + -17

Combine like terms: 0 + -17 = -17
-38c = -17

Divide each side by '-38'.
c = 0.4473684211

Simplifying
c = 0.4473684211

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