(2c+1)=+(6c+8)

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Solution for (2c+1)=+(6c+8) equation: 



(2c+1)=+(6c+8)

We move all terms to the left:

(2c+1)-(+(6c+8))=0

We get rid of parentheses

2c-(+(6c+8))+1=0



We calculate terms in parentheses: -(+(6c+8)), so:

+(6c+8)

determiningTheFunctionDomain
(6c+8)

We get rid of parentheses

6c+8

Back to the equation:

-(6c+8)



We get rid of parentheses

2c-6c-8+1=0

We add all the numbers together, and all the variables

-4c-7=0

We move all terms containing c to the left, all other terms to the right

-4c=7

c=7/-4

c=-1+3/4

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