(2c+12)=68

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Solution for (2c+12)=68 equation: 



(2c+12)=68

We move all terms to the left:

(2c+12)-(68)=0

We get rid of parentheses

2c+12-68=0

We add all the numbers together, and all the variables

2c-56=0

We move all terms containing c to the left, all other terms to the right

2c=56

c=56/2

c=28

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