(2c+2)(3c-1)=

Solution for (2c+2)(3c-1)= equation:

Simplifying
(2c + 2)(3c + -1) = 0

Reorder the terms:
(2 + 2c)(3c + -1) = 0

Reorder the terms:
(2 + 2c)(-1 + 3c) = 0

Multiply (2 + 2c) * (-1 + 3c)
(2(-1 + 3c) + 2c * (-1 + 3c)) = 0
((-1 * 2 + 3c * 2) + 2c * (-1 + 3c)) = 0
((-2 + 6c) + 2c * (-1 + 3c)) = 0
(-2 + 6c + (-1 * 2c + 3c * 2c)) = 0
(-2 + 6c + (-2c + 6c2)) = 0

Combine like terms: 6c + -2c = 4c
(-2 + 4c + 6c2) = 0

Solving
-2 + 4c + 6c2 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '2'.
2(-1 + 2c + 3c2) = 0

Factor a trinomial.
2((-1 + -1c)(1 + -3c)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(-1 + -1c)' equal to zero and attempt to solve:

Simplifying
-1 + -1c = 0

Solving
-1 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1c = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1c = 0 + 1
-1c = 0 + 1

Combine like terms: 0 + 1 = 1
-1c = 1

Divide each side by '-1'.
c = -1

Simplifying
c = -1
Subproblem 2
Set the factor '(1 + -3c)' equal to zero and attempt to solve:

Simplifying
1 + -3c = 0

Solving
1 + -3c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -3c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -3c = 0 + -1
-3c = 0 + -1

Combine like terms: 0 + -1 = -1
-3c = -1

Divide each side by '-3'.
c = 0.3333333333

Simplifying
c = 0.3333333333
Solution
c = {-1, 0.3333333333}