(2c+2)=2(c+2)+3c

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Solution for (2c+2)=2(c+2)+3c equation:


Simplifying
(2c + 2) = 2(c + 2) + 3c

Reorder the terms:
(2 + 2c) = 2(c + 2) + 3c

Remove parenthesis around (2 + 2c)
2 + 2c = 2(c + 2) + 3c

Reorder the terms:
2 + 2c = 2(2 + c) + 3c
2 + 2c = (2 * 2 + c * 2) + 3c
2 + 2c = (4 + 2c) + 3c

Combine like terms: 2c + 3c = 5c
2 + 2c = 4 + 5c

Solving
2 + 2c = 4 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
2 + 2c + -5c = 4 + 5c + -5c

Combine like terms: 2c + -5c = -3c
2 + -3c = 4 + 5c + -5c

Combine like terms: 5c + -5c = 0
2 + -3c = 4 + 0
2 + -3c = 4

Add '-2' to each side of the equation.
2 + -2 + -3c = 4 + -2

Combine like terms: 2 + -2 = 0
0 + -3c = 4 + -2
-3c = 4 + -2

Combine like terms: 4 + -2 = 2
-3c = 2

Divide each side by '-3'.
c = -0.6666666667

Simplifying
c = -0.6666666667

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