(2c+3)/(2c+6)=1/c

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Solution for (2c+3)/(2c+6)=1/c equation: 


D( c )

c = 0

2*c+6 = 0

c = 0

c = 0

2*c+6 = 0

2*c+6 = 0

2*c+6 = 0 // - 6

2*c = -6 // : 2

c = -6/2

c = -3

c in (-oo:-3) U (-3:0) U (0:+oo)

(2*c+3)/(2*c+6) = 1/c // - 1/c

(2*c+3)/(2*c+6)-(1/c) = 0

(2*c+3)/(2*c+6)-c^-1 = 0

(2*c+3)/(2*c+6)-1/c = 0

(c*(2*c+3))/(c*(2*c+6))+(-1*(2*c+6))/(c*(2*c+6)) = 0

c*(2*c+3)-1*(2*c+6) = 0

2*c^2+c-6 = 0

2*c^2+c-6 = 0

2*c^2+c-6 = 0

DELTA = 1^2-(-6*2*4)

DELTA = 49

DELTA > 0

c = (49^(1/2)-1)/(2*2) or c = (-49^(1/2)-1)/(2*2)

c = 3/2 or c = -2

(c+2)*(c-3/2) = 0

((c+2)*(c-3/2))/(c*(2*c+6)) = 0

((c+2)*(c-3/2))/(c*(2*c+6)) = 0 // * c*(2*c+6)

(c+2)*(c-3/2) = 0

( c+2 )

c+2 = 0 // - 2

c = -2

( c-3/2 )

c-3/2 = 0 // + 3/2

c = 3/2

c in { -2, 3/2 }

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