(2c+3)=2(c+5)+c

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Solution for (2c+3)=2(c+5)+c equation: 



(2c+3)=2(c+5)+c

We move all terms to the left:

(2c+3)-(2(c+5)+c)=0

We get rid of parentheses

2c-(2(c+5)+c)+3=0



We calculate terms in parentheses: -(2(c+5)+c), so:

2(c+5)+c

We add all the numbers together, and all the variables

c+2(c+5)

We multiply parentheses

c+2c+10

We add all the numbers together, and all the variables

3c+10

Back to the equation:

-(3c+10)



We get rid of parentheses

2c-3c-10+3=0

We add all the numbers together, and all the variables

-1c-7=0

We move all terms containing c to the left, all other terms to the right

-c=7

c=7/-1

c=-7

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