(2c+5)(2c-5)=

Solution for (2c+5)(2c-5)= equation:

Simplifying
(2c + 5)(2c + -5) = 0

Reorder the terms:
(5 + 2c)(2c + -5) = 0

Reorder the terms:
(5 + 2c)(-5 + 2c) = 0

Multiply (5 + 2c) * (-5 + 2c)
(5(-5 + 2c) + 2c * (-5 + 2c)) = 0
((-5 * 5 + 2c * 5) + 2c * (-5 + 2c)) = 0
((-25 + 10c) + 2c * (-5 + 2c)) = 0
(-25 + 10c + (-5 * 2c + 2c * 2c)) = 0
(-25 + 10c + (-10c + 4c2)) = 0

Combine like terms: 10c + -10c = 0
(-25 + 0 + 4c2) = 0
(-25 + 4c2) = 0

Solving
-25 + 4c2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 4c2 = 0 + 25

Combine like terms: -25 + 25 = 0
0 + 4c2 = 0 + 25
4c2 = 0 + 25

Combine like terms: 0 + 25 = 25
4c2 = 25

Divide each side by '4'.
c2 = 6.25

Simplifying
c2 = 6.25

Take the square root of each side:
c = {-2.5, 2.5}