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(2c+5)(2c-1)=-9
We move all terms to the left:
(2c+5)(2c-1)-(-9)=0
We add all the numbers together, and all the variables
(2c+5)(2c-1)+9=0
We multiply parentheses ..
(+4c^2-2c+10c-5)+9=0
We get rid of parentheses
4c^2-2c+10c-5+9=0
We add all the numbers together, and all the variables
4c^2+8c+4=0
a = 4; b = 8; c = +4;
Δ = b2-4ac
Δ = 82-4·4·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$c=\frac{-b}{2a}=\frac{-8}{8}=-1$
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