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(2c+5)+5c=-2(-3c+2)
We move all terms to the left:
(2c+5)+5c-(-2(-3c+2))=0
We add all the numbers together, and all the variables
5c+(2c+5)-(-2(-3c+2))=0
We get rid of parentheses
5c+2c-(-2(-3c+2))+5=0
We calculate terms in parentheses: -(-2(-3c+2)), so:We add all the numbers together, and all the variables
-2(-3c+2)
We multiply parentheses
6c-4
Back to the equation:
-(6c-4)
7c-(6c-4)+5=0
We get rid of parentheses
7c-6c+4+5=0
We add all the numbers together, and all the variables
c+9=0
We move all terms containing c to the left, all other terms to the right
c=-9
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