(2c+5)+5c=-2(-3c+2)

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Solution for (2c+5)+5c=-2(-3c+2) equation: 



(2c+5)+5c=-2(-3c+2)

We move all terms to the left:

(2c+5)+5c-(-2(-3c+2))=0

We add all the numbers together, and all the variables

5c+(2c+5)-(-2(-3c+2))=0

We get rid of parentheses

5c+2c-(-2(-3c+2))+5=0



We calculate terms in parentheses: -(-2(-3c+2)), so:

-2(-3c+2)

We multiply parentheses

6c-4

Back to the equation:

-(6c-4)



We add all the numbers together, and all the variables

7c-(6c-4)+5=0

We get rid of parentheses

7c-6c+4+5=0

We add all the numbers together, and all the variables

c+9=0

We move all terms containing c to the left, all other terms to the right

c=-9

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