(2c+5)-5c=2(3c+2)+11

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Solution for (2c+5)-5c=2(3c+2)+11 equation: 



(2c+5)-5c=2(3c+2)+11

We move all terms to the left:

(2c+5)-5c-(2(3c+2)+11)=0

We add all the numbers together, and all the variables

-5c+(2c+5)-(2(3c+2)+11)=0

We get rid of parentheses

-5c+2c-(2(3c+2)+11)+5=0



We calculate terms in parentheses: -(2(3c+2)+11), so:

2(3c+2)+11

We multiply parentheses

6c+4+11

We add all the numbers together, and all the variables

6c+15

Back to the equation:

-(6c+15)



We add all the numbers together, and all the variables

-3c-(6c+15)+5=0

We get rid of parentheses

-3c-6c-15+5=0

We add all the numbers together, and all the variables

-9c-10=0

We move all terms containing c to the left, all other terms to the right

-9c=10

c=10/-9

c=-1+1/9

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