(2c+9)(c+5)=

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Solution for (2c+9)(c+5)= equation:


Simplifying
(2c + 9)(c + 5) = 0

Reorder the terms:
(9 + 2c)(c + 5) = 0

Reorder the terms:
(9 + 2c)(5 + c) = 0

Multiply (9 + 2c) * (5 + c)
(9(5 + c) + 2c * (5 + c)) = 0
((5 * 9 + c * 9) + 2c * (5 + c)) = 0
((45 + 9c) + 2c * (5 + c)) = 0
(45 + 9c + (5 * 2c + c * 2c)) = 0
(45 + 9c + (10c + 2c2)) = 0

Combine like terms: 9c + 10c = 19c
(45 + 19c + 2c2) = 0

Solving
45 + 19c + 2c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + c)(9 + 2c) = 0

Subproblem 1

Set the factor '(5 + c)' equal to zero and attempt to solve: Simplifying 5 + c = 0 Solving 5 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + c = 0 + -5 c = 0 + -5 Combine like terms: 0 + -5 = -5 c = -5 Simplifying c = -5

Subproblem 2

Set the factor '(9 + 2c)' equal to zero and attempt to solve: Simplifying 9 + 2c = 0 Solving 9 + 2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + 2c = 0 + -9 Combine like terms: 9 + -9 = 0 0 + 2c = 0 + -9 2c = 0 + -9 Combine like terms: 0 + -9 = -9 2c = -9 Divide each side by '2'. c = -4.5 Simplifying c = -4.5

Solution

c = {-5, -4.5}

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