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Simplifying (2c + -2)(2c + -2) = 0 Reorder the terms: (-2 + 2c)(2c + -2) = 0 Reorder the terms: (-2 + 2c)(-2 + 2c) = 0 Multiply (-2 + 2c) * (-2 + 2c) (-2(-2 + 2c) + 2c * (-2 + 2c)) = 0 ((-2 * -2 + 2c * -2) + 2c * (-2 + 2c)) = 0 ((4 + -4c) + 2c * (-2 + 2c)) = 0 (4 + -4c + (-2 * 2c + 2c * 2c)) = 0 (4 + -4c + (-4c + 4c2)) = 0 Combine like terms: -4c + -4c = -8c (4 + -8c + 4c2) = 0 Solving 4 + -8c + 4c2 = 0 Solving for variable 'c'. Factor out the Greatest Common Factor (GCF), '4'. 4(1 + -2c + c2) = 0 Factor a trinomial. 4((1 + -1c)(1 + -1c)) = 0 Ignore the factor 4.Subproblem 1
Set the factor '(1 + -1c)' equal to zero and attempt to solve: Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms: 0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1Subproblem 2
Set the factor '(1 + -1c)' equal to zero and attempt to solve: Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms: 0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1Solution
c = {1, 1}
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