(2c-5)(2c+5)=

Solution for (2c-5)(2c+5)= equation:

Simplifying
(2c + -5)(2c + 5) = 0

Reorder the terms:
(-5 + 2c)(2c + 5) = 0

Reorder the terms:
(-5 + 2c)(5 + 2c) = 0

Multiply (-5 + 2c) * (5 + 2c)
(-5(5 + 2c) + 2c * (5 + 2c)) = 0
((5 * -5 + 2c * -5) + 2c * (5 + 2c)) = 0
((-25 + -10c) + 2c * (5 + 2c)) = 0
(-25 + -10c + (5 * 2c + 2c * 2c)) = 0
(-25 + -10c + (10c + 4c2)) = 0

Combine like terms: -10c + 10c = 0
(-25 + 0 + 4c2) = 0
(-25 + 4c2) = 0

Solving
-25 + 4c2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 4c2 = 0 + 25

Combine like terms: -25 + 25 = 0
0 + 4c2 = 0 + 25
4c2 = 0 + 25

Combine like terms: 0 + 25 = 25
4c2 = 25

Divide each side by '4'.
c2 = 6.25

Simplifying
c2 = 6.25

Take the square root of each side:
c = {-2.5, 2.5}