(2c-5)2-6=(2c-3)2-6c

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Solution for (2c-5)2-6=(2c-3)2-6c equation: 



(2c-5)2-6=(2c-3)2-6c

We move all terms to the left:

(2c-5)2-6-((2c-3)2-6c)=0

We multiply parentheses

4c-((2c-3)2-6c)-10-6=0



We calculate terms in parentheses: -((2c-3)2-6c), so:

(2c-3)2-6c

We add all the numbers together, and all the variables

-6c+(2c-3)2

We multiply parentheses

-6c+4c-6

We add all the numbers together, and all the variables

-2c-6

Back to the equation:

-(-2c-6)



We add all the numbers together, and all the variables

4c-(-2c-6)-16=0

We get rid of parentheses

4c+2c+6-16=0

We add all the numbers together, and all the variables

6c-10=0

We move all terms containing c to the left, all other terms to the right

6c=10

c=10/6

c=1+2/3

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