(2c-6)-3c=27

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Solution for (2c-6)-3c=27 equation: 



(2c-6)-3c=27

We move all terms to the left:

(2c-6)-3c-(27)=0

We add all the numbers together, and all the variables

-3c+(2c-6)-27=0

We get rid of parentheses

-3c+2c-6-27=0

We add all the numbers together, and all the variables

-1c-33=0

We move all terms containing c to the left, all other terms to the right

-c=33

c=33/-1

c=-33

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