(2c-7)/3=25

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Solution for (2c-7)/3=25 equation: 


c in (-oo:+oo)

(2*c-7)/3 = 25 // - 25

(2*c-7)/3-25 = 0

(2*c-7)/3+(-25*3)/3 = 0

2*c-25*3-7 = 0

2*c-82 = 0

(2*c-82)/3 = 0

(2*c-82)/3 = 0 // * 3

2*c-82 = 0

2*c-82 = 0 // + 82

2*c = 82 // : 2

c = 82/2

c = 41

c = 41

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