(2c-8c+5)+(2c-8c-6=)

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Solution for (2c-8c+5)+(2c-8c-6=) equation: 



(2c-8c+5)+(2c-8c-6=)

We move all terms to the left:

(2c-8c+5)+(2c-8c-6-())=0

We add all the numbers together, and all the variables

(-6c+5)+(2c-8c-6-())=0

We get rid of parentheses

-6c+(2c-8c-6-())+5=0



We calculate terms in parentheses: +(2c-8c-6-()), so:

2c-8c-6-()

We add all the numbers together, and all the variables

-6c

Back to the equation:

+(-6c)



We get rid of parentheses

-6c-6c+5=0

We add all the numbers together, and all the variables

-12c+5=0

We move all terms containing c to the left, all other terms to the right

-12c=-5

c=-5/-12

c=5/12

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