(2d+4)+d+1=1

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Solution for (2d+4)+d+1=1 equation:



(2d+4)+d+1=1
We move all terms to the left:
(2d+4)+d+1-(1)=0
We add all the numbers together, and all the variables
d+(2d+4)=0
We get rid of parentheses
d+2d+4=0
We add all the numbers together, and all the variables
3d+4=0
We move all terms containing d to the left, all other terms to the right
3d=-4
d=-4/3
d=-1+1/3

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