(2d-3)(5d-12)=0

Solution for (2d-3)(5d-12)=0 equation:

(2d-3)(5d-12)=0

We multiply parentheses ..

(+10d^2-24d-15d+36)=0

We get rid of parentheses

10d^2-24d-15d+36=0

We add all the numbers together, and all the variables

10d^2-39d+36=0

a = 10; b = -39; c = +36;
Δ = b2-4ac
Δ = -392-4·10·36
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-9}{2*10}=\frac{30}{20}
=1+1/2
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+9}{2*10}=\frac{48}{20}
=2+2/5
$