(2d-5)(2d+5)=0

Solution for (2d-5)(2d+5)=0 equation:

Simplifying
(2d + -5)(2d + 5) = 0

Reorder the terms:
(-5 + 2d)(2d + 5) = 0

Reorder the terms:
(-5 + 2d)(5 + 2d) = 0

Multiply (-5 + 2d) * (5 + 2d)
(-5(5 + 2d) + 2d * (5 + 2d)) = 0
((5 * -5 + 2d * -5) + 2d * (5 + 2d)) = 0
((-25 + -10d) + 2d * (5 + 2d)) = 0
(-25 + -10d + (5 * 2d + 2d * 2d)) = 0
(-25 + -10d + (10d + 4d2)) = 0

Combine like terms: -10d + 10d = 0
(-25 + 0 + 4d2) = 0
(-25 + 4d2) = 0

Solving
-25 + 4d2 = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 4d2 = 0 + 25

Combine like terms: -25 + 25 = 0
0 + 4d2 = 0 + 25
4d2 = 0 + 25

Combine like terms: 0 + 25 = 25
4d2 = 25

Divide each side by '4'.
d2 = 6.25

Simplifying
d2 = 6.25

Take the square root of each side:
d = {-2.5, 2.5}