(2d-8)(d-3)=2d

Solution for (2d-8)(d-3)=2d equation:

(2d-8)(d-3)=2d

We move all terms to the left:

(2d-8)(d-3)-(2d)=0

We add all the numbers together, and all the variables

-2d+(2d-8)(d-3)=0

We multiply parentheses ..

(+2d^2-6d-8d+24)-2d=0

We get rid of parentheses

2d^2-6d-8d-2d+24=0

We add all the numbers together, and all the variables

2d^2-16d+24=0

a = 2; b = -16; c = +24;
Δ = b2-4ac
Δ = -162-4·2·24
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8}{2*2}=\frac{8}{4}
=2
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8}{2*2}=\frac{24}{4}
=6
$