(2f+50)=(5f-10)

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Solution for (2f+50)=(5f-10) equation: 



(2f+50)=(5f-10)

We move all terms to the left:

(2f+50)-((5f-10))=0

We get rid of parentheses

2f-((5f-10))+50=0



We calculate terms in parentheses: -((5f-10)), so:

(5f-10)

We get rid of parentheses

5f-10

Back to the equation:

-(5f-10)



We get rid of parentheses

2f-5f+10+50=0

We add all the numbers together, and all the variables

-3f+60=0

We move all terms containing f to the left, all other terms to the right

-3f=-60

f=-60/-3

f=+20

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