(2g+4)/6=(g+2)/3

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Solution for (2g+4)/6=(g+2)/3 equation: 



(2g+4)/6=(g+2)/3

We move all terms to the left:

(2g+4)/6-((g+2)/3)=0

We calculate fractions


2g/()+(-((g+2)*6)/()=0



We calculate terms in parentheses: +(-((g+2)*6)/(), so:

-((g+2)*6)/(

We multiply all the terms by the denominator


-((g+2)*6)



We calculate terms in parentheses: -((g+2)*6), so:

(g+2)*6

We multiply parentheses

6g+12

Back to the equation:

-(6g+12)



We get rid of parentheses

-6g-12

Back to the equation:

+(-6g-12)



We get rid of parentheses

2g/()-6g-12=0

We multiply all the terms by the denominator


2g-6g*()-12*()=0

We add all the numbers together, and all the variables

2g-6g*()=0

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