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(2g+4)/6=(g+2)/3
We move all terms to the left:
(2g+4)/6-((g+2)/3)=0
We calculate fractions
2g/()+(-((g+2)*6)/()=0
We calculate terms in parentheses: +(-((g+2)*6)/(), so:We get rid of parentheses
-((g+2)*6)/(
We multiply all the terms by the denominator
-((g+2)*6)
We calculate terms in parentheses: -((g+2)*6), so:We get rid of parentheses
(g+2)*6
We multiply parentheses
6g+12
Back to the equation:
-(6g+12)
-6g-12
Back to the equation:
+(-6g-12)
2g/()-6g-12=0
We multiply all the terms by the denominator
2g-6g*()-12*()=0
We add all the numbers together, and all the variables
2g-6g*()=0
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