(2g+5)(6g-2)=0

Solution for (2g+5)(6g-2)=0 equation:

(2g+5)(6g-2)=0

We multiply parentheses ..

(+12g^2-4g+30g-10)=0

We get rid of parentheses

12g^2-4g+30g-10=0

We add all the numbers together, and all the variables

12g^2+26g-10=0

a = 12; b = 26; c = -10;
Δ = b2-4ac
Δ = 262-4·12·(-10)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-34}{2*12}=\frac{-60}{24}
=-2+1/2
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+34}{2*12}=\frac{8}{24}
=1/3
$