(2g-1)(4g-7)=0

Solution for (2g-1)(4g-7)=0 equation:

(2g-1)(4g-7)=0

We multiply parentheses ..

(+8g^2-14g-4g+7)=0

We get rid of parentheses

8g^2-14g-4g+7=0

We add all the numbers together, and all the variables

8g^2-18g+7=0

a = 8; b = -18; c = +7;
Δ = b2-4ac
Δ = -182-4·8·7
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-10}{2*8}=\frac{8}{16}
=1/2
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+10}{2*8}=\frac{28}{16}
=1+3/4
$