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(2g-2)4g-9=133
We move all terms to the left:
(2g-2)4g-9-(133)=0
We add all the numbers together, and all the variables
(2g-2)4g-142=0
We multiply parentheses
8g^2-8g-142=0
a = 8; b = -8; c = -142;
Δ = b2-4ac
Δ = -82-4·8·(-142)
Δ = 4608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4608}=\sqrt{2304*2}=\sqrt{2304}*\sqrt{2}=48\sqrt{2}$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-48\sqrt{2}}{2*8}=\frac{8-48\sqrt{2}}{16} $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+48\sqrt{2}}{2*8}=\frac{8+48\sqrt{2}}{16} $
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