(2h+1)(h-3)=0

Solution for (2h+1)(h-3)=0 equation:

Simplifying
(2h + 1)(h + -3) = 0

Reorder the terms:
(1 + 2h)(h + -3) = 0

Reorder the terms:
(1 + 2h)(-3 + h) = 0

Multiply (1 + 2h) * (-3 + h)
(1(-3 + h) + 2h * (-3 + h)) = 0
((-3 * 1 + h * 1) + 2h * (-3 + h)) = 0
((-3 + 1h) + 2h * (-3 + h)) = 0
(-3 + 1h + (-3 * 2h + h * 2h)) = 0
(-3 + 1h + (-6h + 2h2)) = 0

Combine like terms: 1h + -6h = -5h
(-3 + -5h + 2h2) = 0

Solving
-3 + -5h + 2h2 = 0

Solving for variable 'h'.

Factor a trinomial.
(-1 + -2h)(3 + -1h) = 0

Subproblem 1
Set the factor '(-1 + -2h)' equal to zero and attempt to solve:

Simplifying
-1 + -2h = 0

Solving
-1 + -2h = 0

Move all terms containing h to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -2h = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -2h = 0 + 1
-2h = 0 + 1

Combine like terms: 0 + 1 = 1
-2h = 1

Divide each side by '-2'.
h = -0.5

Simplifying
h = -0.5
Subproblem 2
Set the factor '(3 + -1h)' equal to zero and attempt to solve:

Simplifying
3 + -1h = 0

Solving
3 + -1h = 0

Move all terms containing h to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1h = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1h = 0 + -3
-1h = 0 + -3

Combine like terms: 0 + -3 = -3
-1h = -3

Divide each side by '-1'.
h = 3

Simplifying
h = 3
Solution
h = {-0.5, 3}