(2h+8)(6h+4)=0

Solution for (2h+8)(6h+4)=0 equation:

(2h+8)(6h+4)=0

We multiply parentheses ..

(+12h^2+8h+48h+32)=0

We get rid of parentheses

12h^2+8h+48h+32=0

We add all the numbers together, and all the variables

12h^2+56h+32=0

a = 12; b = 56; c = +32;
Δ = b2-4ac
Δ = 562-4·12·32
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-40}{2*12}=\frac{-96}{24}
=-4
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+40}{2*12}=\frac{-16}{24}
=-2/3
$