(2h-1)(h-4)=

Solution for (2h-1)(h-4)= equation:

Simplifying
(2h + -1)(h + -4) = 0

Reorder the terms:
(-1 + 2h)(h + -4) = 0

Reorder the terms:
(-1 + 2h)(-4 + h) = 0

Multiply (-1 + 2h) * (-4 + h)
(-1(-4 + h) + 2h * (-4 + h)) = 0
((-4 * -1 + h * -1) + 2h * (-4 + h)) = 0
((4 + -1h) + 2h * (-4 + h)) = 0
(4 + -1h + (-4 * 2h + h * 2h)) = 0
(4 + -1h + (-8h + 2h2)) = 0

Combine like terms: -1h + -8h = -9h
(4 + -9h + 2h2) = 0

Solving
4 + -9h + 2h2 = 0

Solving for variable 'h'.

Factor a trinomial.
(1 + -2h)(4 + -1h) = 0

Subproblem 1
Set the factor '(1 + -2h)' equal to zero and attempt to solve:

Simplifying
1 + -2h = 0

Solving
1 + -2h = 0

Move all terms containing h to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2h = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2h = 0 + -1
-2h = 0 + -1

Combine like terms: 0 + -1 = -1
-2h = -1

Divide each side by '-2'.
h = 0.5

Simplifying
h = 0.5
Subproblem 2
Set the factor '(4 + -1h)' equal to zero and attempt to solve:

Simplifying
4 + -1h = 0

Solving
4 + -1h = 0

Move all terms containing h to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1h = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1h = 0 + -4
-1h = 0 + -4

Combine like terms: 0 + -4 = -4
-1h = -4

Divide each side by '-1'.
h = 4

Simplifying
h = 4
Solution
h = {0.5, 4}