(2k+1)(k+1)(k+4)=

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Solution for (2k+1)(k+1)(k+4)= equation:


Simplifying
(2k + 1)(k + 1)(k + 4) = 0

Reorder the terms:
(1 + 2k)(k + 1)(k + 4) = 0

Reorder the terms:
(1 + 2k)(1 + k)(k + 4) = 0

Reorder the terms:
(1 + 2k)(1 + k)(4 + k) = 0

Multiply (1 + 2k) * (1 + k)
(1(1 + k) + 2k * (1 + k))(4 + k) = 0
((1 * 1 + k * 1) + 2k * (1 + k))(4 + k) = 0
((1 + 1k) + 2k * (1 + k))(4 + k) = 0
(1 + 1k + (1 * 2k + k * 2k))(4 + k) = 0
(1 + 1k + (2k + 2k2))(4 + k) = 0

Combine like terms: 1k + 2k = 3k
(1 + 3k + 2k2)(4 + k) = 0

Multiply (1 + 3k + 2k2) * (4 + k)
(1(4 + k) + 3k * (4 + k) + 2k2 * (4 + k)) = 0
((4 * 1 + k * 1) + 3k * (4 + k) + 2k2 * (4 + k)) = 0
((4 + 1k) + 3k * (4 + k) + 2k2 * (4 + k)) = 0
(4 + 1k + (4 * 3k + k * 3k) + 2k2 * (4 + k)) = 0
(4 + 1k + (12k + 3k2) + 2k2 * (4 + k)) = 0
(4 + 1k + 12k + 3k2 + (4 * 2k2 + k * 2k2)) = 0
(4 + 1k + 12k + 3k2 + (8k2 + 2k3)) = 0

Combine like terms: 1k + 12k = 13k
(4 + 13k + 3k2 + 8k2 + 2k3) = 0

Combine like terms: 3k2 + 8k2 = 11k2
(4 + 13k + 11k2 + 2k3) = 0

Solving
4 + 13k + 11k2 + 2k3 = 0

Solving for variable 'k'.

The solution to this equation could not be determined.

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