(2k+1)/(3+k)=-1

Solution for (2k+1)/(3+k)=-1 equation:

(2k+1)/(3+k)=-1

We move all terms to the left:

(2k+1)/(3+k)-(-1)=0


Domain of the equation: (3+k)!=0

We move all terms containing k to the left, all other terms to the right

k!=-3

k∈R


We add all the numbers together, and all the variables

(2k+1)/(k+3)-(-1)=0

We add all the numbers together, and all the variables

(2k+1)/(k+3)+1=0

We multiply all the terms by the denominator


(2k+1)+1*(k+3)=0

We get rid of parentheses

2k+1*(k+3)+1=0

We move all terms containing k to the left, all other terms to the right

2k+1*(k+3)=-1