(2k+1)=3(k+4)

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Solution for (2k+1)=3(k+4) equation:


Simplifying
(2k + 1) = 3(k + 4)

Reorder the terms:
(1 + 2k) = 3(k + 4)

Remove parenthesis around (1 + 2k)
1 + 2k = 3(k + 4)

Reorder the terms:
1 + 2k = 3(4 + k)
1 + 2k = (4 * 3 + k * 3)
1 + 2k = (12 + 3k)

Solving
1 + 2k = 12 + 3k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-3k' to each side of the equation.
1 + 2k + -3k = 12 + 3k + -3k

Combine like terms: 2k + -3k = -1k
1 + -1k = 12 + 3k + -3k

Combine like terms: 3k + -3k = 0
1 + -1k = 12 + 0
1 + -1k = 12

Add '-1' to each side of the equation.
1 + -1 + -1k = 12 + -1

Combine like terms: 1 + -1 = 0
0 + -1k = 12 + -1
-1k = 12 + -1

Combine like terms: 12 + -1 = 11
-1k = 11

Divide each side by '-1'.
k = -11

Simplifying
k = -11

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