(2k+1)=3(k+4)5

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Solution for (2k+1)=3(k+4)5 equation:



(2k+1)=3(k+4)5
We move all terms to the left:
(2k+1)-(3(k+4)5)=0
We get rid of parentheses
2k-(3(k+4)5)+1=0
We calculate terms in parentheses: -(3(k+4)5), so:
3(k+4)5
We multiply parentheses
15k+60
Back to the equation:
-(15k+60)
We get rid of parentheses
2k-15k-60+1=0
We add all the numbers together, and all the variables
-13k-59=0
We move all terms containing k to the left, all other terms to the right
-13k=59
k=59/-13
k=-4+7/13

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