(2k+3)(2)=

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Solution for (2k+3)(2)= equation:



(2k+3)(2)=
We move all terms to the left:
(2k+3)(2)-()=0
We add all the numbers together, and all the variables
(2k+3)2=0
We multiply parentheses
4k+6=0
We move all terms containing k to the left, all other terms to the right
4k=-6
k=-6/4
k=-1+1/2

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