(2k+3)+(4k-3)=90

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Solution for (2k+3)+(4k-3)=90 equation: 



(2k+3)+(4k-3)=90

We move all terms to the left:

(2k+3)+(4k-3)-(90)=0

We get rid of parentheses

2k+4k+3-3-90=0

We add all the numbers together, and all the variables

6k-90=0

We move all terms containing k to the left, all other terms to the right

6k=90

k=90/6

k=15

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